NCERT Solutions For Class 5 Maths Chapter 11 Area And Its Boundary -

NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary are helpful resources for students learning about area and its boundary in mathematics. This chapter teaches students how to measure area using different units. The solutions cover topics like square units, calculating the area of squares and rectangles, and understanding shape perimeters. By using NCERT Solutions for Class 5 Maths Chapter 11, students can improve their problem-solving skills and develop a strong foundation in mathematics.

NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary has been published by exammodalpaper. You can now download the NCERT Solutions for Class 5 Maths Chapter 11 Area and its Boundary Questions and Answers PDF here. This NCERT Solutions for Class 5 Maths contains answers of all questions asked in Chapter 8 in textbook. Therefore you can prerefer it to solve Be My Multiple, I’ll be Your Factor exercise questions and learn more about the topic.In lesson 11 of Class 5 Maths, students learn .

NCERT Solutions for Class 5 Maths Chapter 11 are prepared by experienced educators who have a deep understanding of the curriculum and the needs of students. These solutions are accessible and serve as an invaluable resource for self-study and revision.

Table of Contents

NCERT Solutions for class 5 Maths Chapter 11 Area and its Boundary

Whose Slice is Bigger?

Parth and Gini bought aam pappad (dried mango slice) from a shop. Their pieces looked like these.

Both could not make out whose piece was bigger.

1. Suggest some ways to find out whose piece is bigger. Discuss.

Ans: The length of piece A is 6 cm.

So 6 squares of side 1 cm can be arranged along its length.

The width of piece A is 5 cm.

So 5 squares can be arranged along its width.

Altogether 30 squares can be arranged on it.

So, the area of piece A = 6 cm × 5 cm = 30 square cm

2. Altogether how many squares can be arranged on it? ________

Ans: 30

3. So the area of piece A = ________ square cm

So the area of piece A = 30 square cm

4. In the same way find the area of piece B.

Ans: Now, the area of piece B = 11 cm × 3 cm = 33 square cm

5. Who had the bigger piece? How much bigger?

Ans: So, the area of piece B is bigger than the area of piece A.

Difference in area of piece A and piece B = 33 − 30 = 3 square cm

So, piece B is 3 square cm bigger than piece A.

Question 1: This stamp has an area of 4 square cm. Guess how many such stamps will cover this big rectangle.

Answer: Guess on your own. Answers may vary. About 28 such stamps can cover the big rectangle.

Question 1:

a) Measure the yellow rectangle. It is ________ cm long.
b) How many stamps can be placed along its length? ________
c) How wide is the rectangle? ________ cm.
d) How many stamps can be placed along its width? ________
e) How many stamps are needed to cover the rectangle? ________
f) How close was your earlier guess? Discuss.
g) What is the area of the rectangle? ________ square cm.
h) What is the perimeter of the rectangle? ________ cm.

Answer: a) 14cm.
b) 7 stamps.
c) It is 8 cm wide.
d) 4 stamps
e) 28 stamps are needed to cover the rectangle.
f) Do it by yourself.
g)Area of rectangle = 7 × 4 = 28 square cm
h) Perimeter of a rectangle can be found by:
Perimeter = 2 (Length + Width)
Therefore, the perimeter of the rectangle is:
2(7 + 4) = 2 × 11 = 22 cm.

a) Arbaz plans to tile his kitchen floor with green square tiles. Each side of the tile is 10 cm. His kitchen is 220 cm in length and 180 cm wide. How many tiles will he need?

Ans :-Area of floor = length x width
= 220 x 180 = 39600 square cm Area of a tile = Side x Side
= 10 x 10 = 100 square cm Number of tiles = Area of floor + Area of tile
= 39600 + 100 = 396 tiles

Question 3: b) The fencing of a square garden is 20 m in length. How long is one side of the garden?

Ans. Perimeter of garden = 20 m
Hence, length of each side = 20 + 4 = 5 m

c) A thin wire 20 centimeters long is formed into a rectangle. If the width of this rectangle is 4 centimeters, what is its length?

Ans. Perimeter = 20 cm
Width = 4 cm
We know, perimeter = 2(length + breadth)
Hence, 2 (length + breadth) = 20
Or, length + 4 = 20÷2 = 10
Or, length = 10 – 4 = 6 cm

(d)A square carromboard has a perimeter of 320 cm. How much is its area?
Ans. Perimeter = 320 cm
We know, perimeter = 4 x Side Hence, 4 x Side = 320 cm Or, Side = 320 4 = 80 cm
Now, area = Side x Side
= 80 x 80 = 6400 square cm

Question 6: e) How many tiles like the triangle given here will fit in the white design? Area of design = ___________ square cm.

Answer: Observe the given design. There is 1 square and 4 triangles. Since the triangle is half of a cm square, 6 triangular tiles can fit in the design. Area of design = 3 square cm.

Question 7: f) Sanya, Aarushi, Manav, and Kabir made greeting cards. Complete the table for their cards:

Answer: Step 1: Consider Sanya’s card:
Length = 10 cm, width = 8 cm. It is a rectangle.
Perimeter = 2(length + width) = 2(10 + 8) = 2 × 18 = 36 cm
Area = length × width = 10 × 8 = 80 square cm
Step 2: Consider Manav’s card:
Length = 11 cm, perimeter = 44 cm
Perimeter = 44 = 4 × 11 = 4 × length.
So, Manav’s card is a square.
Therefore,
Width = Length = 11 cm = Side of the square
Area = Side × Side = 11 × 11 = 121 square cm.
Step 3: Consider Arushi’s card:
Width = 8 cm, area = 80 square cm.
Area = Length × Width
⇒ Length = Area ÷ Width = 80 ÷ 8 = 10 cm. So, it is a rectangle.
Perimeter = 2 (length + width) = 2(10 + 8) = 2 × 18 = 36 cm
Step 4: Consider Kabir’s card:
Perimeter = 40 cm, area = 100 square cm.
Perimeter = 40 = 4 × 10
Area = 10 × 10 = 100 square cm.
So, Kabir’s card is a square with side 10 cm. Therefore,
Length = 10 cm, width = 10 cm.
The correct answer is:

Question 8: Take a thick paper sheet of length 14 cm and width 9 cm. You can also use an old postcard.
a) What is its area?
b) What is its perimeter?
c) Now cut strips of equal sizes out of it. Using tape join the strips, end to end, to make a belt. How long is your belt? _________
d) What is its perimeter _________
e) Whose belt is the longest in the class? ________

Ans:- a)Length of paper sheet = 14 cm

Breadth of paper sheet = 9 cm

Area of the sheet = 14 cm × 9 cm = 126 square cm

Perimeter of the sheet = 14 cm + 9 cm + 14 cm + 9 cm = 46 cm

b)How long is your belt? _____

ans:- 84 cm

c) What is its perimeter _____?

ans :- 90 cm

other Answer: Do it by yourself.
Area = 14 × 9 = 126 square cm.
Perimeter = 14 + 9 + 14 + 9 = 46 cm.

Question 1: A) Make two squares of one square metre each. Divide your class in two teams. Ready to play! Try these in your teams:
a) How many of you can sit in one square metre? ________
b) How many of you can stand in it? ________
c) Which team could make more children stand in their square? How many? ________
d) Which team could make more children sit in their square? How many?

Answer: Do it by yourself with the help of your friends. Answers may vary.

Question 2: B) Measure the length of the floor of your classroom in metres. Also measure the width.
a) What is the area of the floor of your classroom in square metres? __________
b) How many children are there in your class? _________
c) So how many children can sit in one square metre? __________
d) If you want to move around easily then how many children do you think should be there in one square metre? _________

Answer: Do it by yourself as directed. Use a measuring tape to measure the length and width of the floor of your classroom. Answers may vary.

Question 1: Nasreena is a farmer who wants to divide her land equally among her three children — Chumki, Jhumri and Imran. She wants to divide the land so that each piece of land has one tree. Her land looks like this.

a) Can you divide the land equally? Show how you will divide it. Remember each person has to get a tree. Colour each person’s piece of land differently.
b) If each square on this page is equal to 1 square metre of land, how much land will each of her children get? ___________ square m Chumki, Jhumri and Imran need wire to make a fence.
c) Who will need the longest wire for fencing? __________
d) How much wire in all will the three need? ___________

Answer: a)Total number of boxes = 90

Hence, one person’s share is = 90/3

= 30 boxes.

The division can be done as shown in the given figure:

b) 30 square metre
c)Perimeter of Chumki’s land = 9 + 2 + 3 + 2 + 6 + 4 = 26 m

Perimeter of Jhumri’s land = 6 + 3 + 2 + 3 + 4 + 6 = 24 m

Perimeter of Imraan’s land = 8 + 5 + 3 + 2 + 5 + 3 = 26 m

So it is clear that Chumki and Imraan need longest wire of fencing.

d) Total length of wire = 26 + 24 + 26 = 76 m

Practice Time
1.Look at the table. If you were to write the area of each of these which column would you choose? Make a (Right)
Ans.
NCERT Solutions for Class 5 Maths Chapter 11 Area and Its Boundary Page 153 Q1

1.Draw a square of 9 square cm. Write A on it.
Draw another square with double the side. Write B on it.
NCERT Solutions for Class 5 Maths Chapter 11 Area and Its Boundary Page 154 Q1
The perimeter of square A is 12 cm.
The side of square B is 6 cm.
The area of square B is 36 square cm.
The area of square B is 4 times the area of square A.
The perimeter of square B is 24 cm.
The perimeter of square B is 2 times the perimeter of square A.

Save the Birds:

There are two beautiful lakes near a village. People come for boating and picnics in both the lakes. The village Panchayat is worried that with the noise of the boats the birds will stop coming. The Panchayat wants motor boats in only one lake. The other lake will be saved for the birds to make their nests.

(а)How many cm is the length of the boundary of lake A in the drawing?……………..(use thread to find out).
Ans. 33 cm
(b)What is the length of the boundary of lake B in the drawing?
Ans. 26 cm
(c)How many kilo metres long is the actual boundary of lake A?
Ans. 33 km 14
(d) How many kilometres long is the actual boundary of lake B?
Ans. 26 km
(e) A longer boundary around the lake will help more birds to lay their eggs. So which lake should be kept for birds? Which lake should be used for boats?

Ans. Lake A should be kept for birds and lake B should be used for boats.
(f) Find the area of lake B on the drawing in square cm. What is its actual area in square km?
Ans. Number of complete squares = 15 Number of half squares = 3 Number of more than half squares = 8
Hence, area = (15 + 3 x 1/2 + 8)
= 24 (i/2) square cm
Hence, actual area of lake B = 24 (1/2) square km

King’s Story
The king was very happy with carpenters Cheggu and Anar. They had made a very big and beautiful bed for him. So as gifts the king wanted to give some land to Cheggu, and some gold to Anar.
Cheggu was happy. He took 100 metres of wire and tried to make different rectangles.
He made a 10 m x 40 m rectangle. Its area was 400 square metres.
So he next made a 30 m x 20 m rectangle.

1.What is its area? Is it more than the first rectangle?
Ans. Area of rectangle = 30 x 20 = 600 square metres Yes, it is more than the first rectangle

2.What other rectangles can he make with 100 metres of wire. Discuss which of these rectangles will have the biggest area.
Ans. Following rectangles are possible:
5 m x 45 m = 225 square m
15 m x 35 m = 525 square m
25 m x 25 m = 625 square m
The square will have the biggest area.

3.Cheggu’s wife asked him to make a circle with the wire. She knew it had an area of 800 square metres. Why did Cheggu not choose a rectangle? Explain.
Ans. Because none of the rectangle will have an area of 800 square meter.

So Anar also tried many different ways to make a boundary for 800 square metres of land.He made rectangles A, B and C of different sizes. Find out the length of the boundary of each. How much gold wire will he get for these rectangles?
(a)40 m x 20 m
Perimeter = 2(length + breadth) = 2 (40 + 20) = 2 x 60 = 120 m
(b)80 m x 10 m
Perimeter = 2(length + breadth) = 2(80 + 10) = 2 x 90 = 180 m
(c)800 m x 1 m
Perimeter = 2(length + breadth) = 2 (800 + 1) = 2 x 801 = 1602 m
But then Anar made an even longer rectangle See how long!
(d)8000 m x 0.1 m
Perimeter = 2(length + breadth) = 2(8000 + 0.1) = 2 x 8000.1 = 16000.2 m
1.Now do you understand why the king fainted!!
Ans. The king fainted because he could not arrange so much of gold.

2.Can you make a rectangle with a still longer boundary? I made a rectangle 1 cm wide and 80000 m long. Imagine how long that boundary will be!!! With that much gold wire I can become a king!
Ans. Perimeter = 2(length + breadth)
2(80000 m + 1 cm)
= 2(80000 m + 1/100 m)
= 2(80000 m + 0.01 m)
= 2 x 80000.01 m = 16000.02 m

NCERT Solutions for class 5 Maths Chapter 11 Area and its Boundary

NCERT Solutions for class 5 Maths Chapter 11 Area and its Boundary

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